Question

Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56,then, difference of first and third numbers is

Answer 1

Step-by-step explanation:

let the first number be x.

second number=×/2=a

third number=2x=b

average=(x+a+b)/3=56

=(x+x/2+2x)/3=56

=(7x/2)/3=56

x=(56×2×3)/7

=48

first number =48

srcond number=48/2=24

third number=48×2=96