Question

Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, then difference of the first and third number is ​

Answer 1

Let the second number be x

Then, first number = 2x,

3rd number = 4x

∴ 2x + x + 4x = 56 × 3

⇒ 7x = 168

⇒ x = 24∴

Required difference= 4x - 2x

= 2x=

2 × 24= 48

third =2x−x=x=48.

Answer 2

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