Question

Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, then difference of the first and third number is 
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Answer 1

Answer:

Let the first number be x and y be the second number and z be the third number

given that, x = 2.y and x = z/2

Then, Second number(y) =

2

x

Third number(z) =2x

Given,

3

x+

2

x

+2x

=56⇒

6

7x

=56⇒x=

7

56×6

48

∴ Difference between first and third =2x−x=x=48.

Step-by-step explanation:

hope it is helpful for you

Answer 2

= 48

Step-by-step explanation:

Let the second number be x

Then, first number = 2x, 3rd number = 4x

∴ 2x + x + 4x = 56 × 3

⇒ 7x = 168

⇒ x = 24

∴ Required difference

= 4x - 2x

= 2x

= 2 × 24

= 48

HOPE YOU GET YOUR SOLUTION⛄