Out of three numbers, the first is twice the second and is half the third. If the average of the three numbers is 56, then the difference of the first and third number is equal to
a) 12
b) 20
c)24
d)48
. Please answer correctly and , there should a step by step explanation.
Answers
Answered by
0
Answer:
Step-by-step explanation:
Suppose taking three value x,y,z
If. First is twice is twice the second then
2x+y
And it is half of it's third then 2x+y+1/2x.z=56
Then 2x+y+z=112
2x=112-y-z
X=56-y-z-----------1)
Putting the value
2.56+y+1/2z
Answered by
0
Let nos be x, x/2,2x
x+x/2+2x=168
x=48
2x=96
difference=48
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