Question

outer diameter of a metallic tube is 14 cm and thickness of the tube is 1 cm find the weight of 2 metre long tube the density of the metal is 7 gram/cm square​

Answer 1

$\sf\underline\red{Given:}$

• Outer diameter of the tube $\rm{=14cm}$
• Density of the metal $\rm{=7\:gm/cm³}$
• Thickness of the tube $\rm{=1\:cm}$

$\sf\underline\blue{To\:find:}$

→The weight of $\rm{2\:m}$ metre long tube if its density is $\rm{7\:gm/cm³}$

$\sf\underline\orange{Solution:}$

If the outer diameter of the tube $\rm{=14\:cm}$, then the outer radius of the tube is$\rm{(R)7\:cm}$

Thickness of tube=$\rm{1\:cm}$

Inner radius of the tube(r) $\rm{=7-1=6\:cm}$

Lenght of the tube(h) $\rm{=2m=200\:cm}$

$\sf\pink{→We\:have\:to\:find\:the\: weight\:of\:tube:-}$

$\rm\fbox\green{Weight\:of\: tube=Volume\: of\:metal\:in \:tube × Density\:of\:metal}$

$\sf{Volume\:of\:metal\:in\:tube=πR²h-πr²h}$

$\sf{Volume\:of\:metal\:in\:tube=π(R²-r²)h}$

$\sf{Volume\:of\:metal\:in\:tube=}\dfrac{22}{7}(7²-6²)×200cm³$

$\sf{Volume\:of\:metal\:in\:tube=}\dfrac{22}{7}(49-36)×200cm³$

$\sf{Volume\:of\:metal\:in\:tube=}\dfrac{22}{7}×13×200cm³$

$\sf{Weight\:of\:the\:tube=}\dfrac{22}{7}×13×200×7gm$

$\sf{=57,200\:gm}$

Hence, the weight of the tube is $\sf{57,200\:gm.}$

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Hope it's helpful

Answer 2

Answer:

Step-by-step explanation:

Hey there refer to attachment hope it helps:)

AbhiraSingh