Question

Outline the steps of formation of compound Sodium chloride​

Answer 1

Answer:

When sodium reacts with chlorine, it transfers its one outermost electron to the chlorine atom. By losing one electron, sodium atom forms a sodium ion (Na+) and by gaining one electron, the chlorine atom forms a chloride ion (Cl-). ... Thus, sodium chloride is an ionic compound and contains ionic bonds.

Answer 2

Answer:

Bond formation in Sodium Chloride (NaCl)

NaCl is an ionic solid.

The general electronic configurations are...

Na−1S22S22P63S1

Cr−1S22S22P63S23P5

Na is in excess of one electron to attain octet configuration.

Cl has one electron less to attain octet configuration.

So, the excess one electron is transferred to a chlorine atom from Na(sodium) atom and thus an ionic bond is formed due to the transfer of electrons. Chloride being a mole electronegative atom than sodium tends to attract the shared electron pair towards itself.

Thus NaCl has Na+ and Cl− atoms.

Na+−Cl−

Chloride attains octet configuration by gaining on the electron.

Sodium attains octet configuration by losing the electron.

Thus Ionic solid NaCl is stable.

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