Question

Output: int x=1; do { System.out.print(x+":"); ++x;}while(x++<=5);​

Answer 1

Answer:

Import java.util.*;

public class xyz

{

public static void main()

{

Scanner sc= new scanner ( System.in);

int z= sc.nextInt();

int x=sc.nextInt();

int y=sc.nextInt();

z= (5*x*x*x+2*y)/(x+y);

System.out.println(“the required expression is”+z);

}

}

You can input data members via Buffer also

You can take the data type as Double also.

742 viewsView 1 Upvoter

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Answer 2

JAVA CODE

class HelloWorld {

   public static void main(String[] args) {

          int x=1;

     do { System.out.print(x+":"); ++x;}

     while(x++<=5);

   }

}

Output

1:3:5:

• The if and else conditions have both been given. Only when the if block's condition is met will the print statement of the if block run. If not, the else block's print statement will be carried out. The Java programme to check eligibility for voting is provided below.
• the Java System. An argument supplied to println() is printed using this function.
• In your example, the evaluation of the expression contained within the if(expression) statement results in a call to printf. If the body (blank in your case) of the if is run depends on the value of this expression. Activate this post's status. The printf() function returns the total number of printed characters.

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