output of program
#include
using namespace std;
int result(int n)
{
if(n<=10)
return n;
else
{
int a= n%10;
int b= n/10;
return a+ result(a+b);
}}
int main()
{
cout<
return 0;
}
Answers
Answered by
1
Answer:
This will throw an error.
Explanation:
Because cout is missing one angular bracket (<) and also because cout cannot return 0;
If there was another statement then that statement will have been printed instead (However it should not be a keyword)
If you want output of the function result then you should call it in the main function by supplying a number to be assigned to n in result function.
Without your preferred value of n, I cannot tell you the output/working of the result function.
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