outside the boundary of a circular ground of radius 15 metre there is a circular path of uniform width of 5 metre find the area of a path
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Answer:
Step-by-step explanation:
radius of circle= 41m
inner radius = 41-5 = 36m
area of path =π(41^2 - 36^2) = 1209.5 m^2
cost = 1209.5 × 25 = 30237.8
Answered by
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Step-by-step explanation:
Radius of full fig. = 20 m
Area '' " " = (22×20×20)÷7
= (8800÷7)m²
Area of ground = (22×15×15)÷7
= {(225×22)÷7}m²
Area of path = (880÷7)-{(225×22)÷7}
= (8800-4950)÷7
= 3850÷7
= 578.57m² (approx.)
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