Question

Over a period of 6 weeks, a book company packed 568 boxes with books. Each box was 25 cm by 15 cm by 20 cm and had to be taped as shown. 5 cm of overlap was required on both tapes. a. Find the total length of tape used b. How many rolls of tape, each 75 cm long, were required to tape the boxes?

Answer 1

$\sf\blue{ANSWER}$

For each box,The total length is the sum of the perimeter along the sides.

$\implies\rm{2(l+b)+2(l+h}$

$\implies\rm{2(15+20)+2(20+25)=2(35)+2(45)=70+90=160cm.}$

So, For 568 Boxes.

$\implies\rm{568(10)=90880cm=908.8cm}$

Now, Divide the total length of boxes by 75m to find the number of rols of tape to be used.

$\implies\rm{\dfrac{\cancel{908.8}}{\cancel{75}}=12.12}$

Since, You cannot have a frictional number of rolls of tape we round up to 13 rolls of tape.