Question

over a solenoid of 50cm length and 2cm radius and having 500 turns, is wound another wire of 50 turns, coaxially. Calculate the induced emf in the second coil when the current in the primary changes from 0-5A in 0.02 second is​

Answer 1

Answer:

19.74 mV

Explanation:

here we need to find magnetic induction first

M=meu0(n1 n2)A/l

• n1 given as 500
• n2 given as 50

by substitution we get M as 0.00007896 H

and emf =M di/dt

• di=5
• dt=0.02

thus e= 19.74mV