Question

Over the course of an 8 hour day, 3.8x104 C of charge passes through a typical computer (presuming it is in use the entire time). Determine the current for such a computer.

Answer 1

Given :

Charge passing ${q=3.8}$×$10^{4}$ C = 38000 C

time of passing ${t=8 hours}$  = 8×60×60 = 28800 s

To find :

Current (I) = ?

Solution:

Current for computer $I = \frac{q}{t}$

$I = \frac{38000}{28800}$

${I = 1.32 A}$

Hence the current passing through the computer is 1.32 A