Question

over
The speed of
lookm/h to 7km/h
of soon
diclance
coming
is reduced from
distance
fluid uniform retordation
further travelled before
to rest.
andद स्पीड ऑफ 1 कार इज रिड्यूस्ड फ्रॉम हंड्रेड किलोमीटर टू 7 किलोमीटर पर आवर ओवर ए डिस्टेंस ऑफ 500 मीटर फुल यूनिफॉर्म रेटरडेशन एंड डिस्टेंस फॉर द टेबल बिफोर कमिंग टूरिस्ट ​

Answer 1

Answer:

Answer

Correct option is

A

10 m

initial speed u=36×5/18=10m/s

final speed v=9×5/18=2.5m/s

using v

2

=u

2

−2as, with a=150meter

we get a=

150×2

100−6.25

=0.3125m/s

2

now taking u=2.5m/s and v=0(rest) with a=0.3125 for the second case

we get s=

2×0.3125

6.25

=10meter

Explanation:

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follow

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Answer 2

Answer:

A car trvelling at 108kmh-1 has its speed reduced to 36kmh-1 after traelling a distance of 2000m Find the retardation (assumed uniform) and time taken for this process. v=u+at⇒10=30-2t⇒t=10s