Question

Over which interval does hhh have a negative average rate of change? h(t)= (t+3)^2 + 5h(t)=(t+3) 2 +5

Answer 1

Given:

h(t)=(t+3)² +5

To Find:

The interval in which h(t) have a negative average rate of change.

Solution :

Given h(t)=(t+3)² +5 .

Rate of change of a function is given by its derivative.

Therefore to find rate of change of h(t) , find the derivative of h(t).

• d h(t) / dt = 2( t + 3 )
• h ' ( t ) = 2 ( t + 3 ) < 0
• t  < -3

Therefore h ' (t) is negative for all values of less than -3.

The interval over which h have a negative average rate of change is

( -∞, -3 )