ownlm.
Find the area of a rhombus given that its side measures 13 cm and one of diagonals
measures 10 cm.
mkrishnan:
60 is the answer
Answers
Answered by
0
area of rhombus=base*altitude
=13*10
=130 cmsq.
Answered by
4
diagonals of rhombus are perpendicular bisectors each other
therefore
measure of other diagonal of rhombus=√ (13)²- (5)²
= √169 - 25
=√144
= 12
= 2 × 12 = 24 cm
Now
area of rhombus= 1/2 × first diagonal × second diagonal
= 1/2 × 10 × 24
= 12 × 10
= 120 sq.cm.
Hope it will help you
therefore
measure of other diagonal of rhombus=√ (13)²- (5)²
= √169 - 25
=√144
= 12
= 2 × 12 = 24 cm
Now
area of rhombus= 1/2 × first diagonal × second diagonal
= 1/2 × 10 × 24
= 12 × 10
= 120 sq.cm.
Hope it will help you
Similar questions