Question

Oxidation no of c in c12h22o11

Answer 1

Let, oxidation number of C = x

So, 12x + 22×1 + (11×-2) = 0

(Here,12×o.n of C + 22× o.n of H+11×o.n of O)

12x + 22 - 22 = 0

12x - 0 = 0

Ans. x = 0

(note :- o.n = oxidation number)