oxidation no of c in c2h4o
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Step-by-step explanation:
O always has an oxidation number of 2- and H always has an oxidation of +1. So 6 H and 1 O equals +4. The overall charge is 0, so C2 must equal -4, so one C is -2. C in C2H4O on the products said has a charge of -1.
Answered by
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C2 H4 O = 2C + 4(1) + (-2) = 0
2C +4-2 = 0
2C +2 = 0
C= -2/2
C = -1
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