Oxidation no of (fe(h2o)5(no)+)so4
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number of SO4= -2
number of H2O= 0
number of NO= -1
Therefore ON of Fe= -(-1+0–2)=+3
The correct structure is [FeIII(H2O)5(NO−)]2+
For many years it was thought that iron was reduced to FeI and NO oxidized to NO+ ,based upon an observed magnetic moment suggestive of three unpaired electrons, however, the current thinking is that high spin FeIII (S=5/2) antiferromagnetically couples with NO-(S=1) for an observed spin of S=3/2.
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