Chemistry, asked by yashu555, 1 year ago

Oxidation no. Of metals in [Fe(CN)6]^4-

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Answered by sachinsaini2225
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the groups ferrocyanide have the charge -4, given from 6 ions CN− with charge -1 and a atom of iron with charge +2. Each [Fe(Fe(CN)6)] is then a −1 , so with each [Fe(CN)6]4− being a 4− charge, the bolded iron is a +3

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