Question

oxidation no of Mn in KMnO4

Answer 1

The oxidation state of Mn in KMnO4 is +7. This can be obtained by taking into account the valencies of potassium and oxygen atoms. The valency of K is 1 but it loses electron so to be specific it is +1. Similarly oxygen in specific has a valency of -2.

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Answer 2

∆Oxidation state of k is +1 and oxidation State of oxygen is -2 and the total oxidation no of the compound is zero.
∆Then,
$1(1) + x + 4( - 2) = 0$
$1 + x - 8 = 0$
$x = 8 - 1$
$x = + 7$
∆ This is the answer.
∆ Be Brainly.