oxidation no of N in NH₃ is what and how to find oxidation fora chemical equation
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Answered by
2
Oxidation of Hydrogen is 1.So there are three molecules of hydrogen.So oxidation
number of H3 = 3(1) = 3
So we need to make the overall oxidation number of NH3 should be zero as it is in its free state.
So only 3(O.no of H3) + __ (O.no of N) = 0
3+O.no of N = 0
O.no of N = -3
In this method oxidation of different compounds can be found.
number of H3 = 3(1) = 3
So we need to make the overall oxidation number of NH3 should be zero as it is in its free state.
So only 3(O.no of H3) + __ (O.no of N) = 0
3+O.no of N = 0
O.no of N = -3
In this method oxidation of different compounds can be found.
keerthika1998lekha:
N in N3h . oxidation no of H = 1 , N = ?....total oxidation = 0
so 3(N) + 1 = 0
3N = - 1
N = -1/3
ok got it thanks alot u helped me so much na hence i marked u as best
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nd welcome
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Answered by
1
Oxidation number of hydrogen is 1 (we know)
and total charge is zero so
N+3=0
N=-3
if you are considering about n3h
then oxidation number is
let consider n be "x"
3x+1=0
x=-1/3
so oxidation number of n3h is =-1/3
and total charge is zero so
N+3=0
N=-3
if you are considering about n3h
then oxidation number is
let consider n be "x"
3x+1=0
x=-1/3
so oxidation number of n3h is =-1/3
ok i will ask another question
thanks...............
u also helped me so much thanks
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