Oxidation no of p in ca(h2po3)2
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Answer:
+5
Explanation:
Oxidation states of :
H =+1
O =-2
Ca=+2
P=?
Ca(H2PO3)2
=>[(H2PO3)2]^+2
=> [(+1x2)+(Xx1)+(-2x3)]x2 = +2
=> [+2+X-6]x2 =+2
=> +4+2X-12 =+2
=> 2X- 8=+2
=> 2X =10
=> X=+5
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