Chemistry, asked by mibrahimgazi11, 10 months ago

oxidation no. of P in NaH2 PO4​

Answers

Answered by saipranadk
1

Answer:

+5

Explanation:

The oxidation number of a compound is 0. That indicates oxidation number of the whole compound, NaH2PO4, is 0. That means, the individual oxidation of each element adds up to zero.

Points to remember:

The oxidation number of group 1 elements is always +1

Oxidation number of H is +1 in most of the cases. (This is one of the cases)

Oxidation number of O is -2 in most of the cases. (This is one of the cases)

Let the oxidation number of P is x

So, +1 + 2(+1) + x + 4(-2) = 0

1 + 2 + x - 8 = 0

x = +5

Therefore the oxidation state of P in NaH2PO4 is+5.

Thanks. :)

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