oxidation no. of P in NaH2 PO4
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Answer:
+5
Explanation:
The oxidation number of a compound is 0. That indicates oxidation number of the whole compound, NaH2PO4, is 0. That means, the individual oxidation of each element adds up to zero.
Points to remember:
The oxidation number of group 1 elements is always +1
Oxidation number of H is +1 in most of the cases. (This is one of the cases)
Oxidation number of O is -2 in most of the cases. (This is one of the cases)
Let the oxidation number of P is x
So, +1 + 2(+1) + x + 4(-2) = 0
1 + 2 + x - 8 = 0
x = +5
Therefore the oxidation state of P in NaH2PO4 is+5.
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