oxidation no of s H2SO3
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right answer.............
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Hey dear ,
Down Here.
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Oxidation no. of Hydrogen = +1
Oxidation no. of Oxygen = -2
Now,
Since H2SO3 is charge less.
Therefore,
H2 SO3 = 0
1(2) + S(1) + -2(3) = 0
2 +S - 6 = 0
S - 4 = 0
S = +4
Thus oxidation no. of Sulphur in H2SO3 is +4.
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Hope it helps....
Down Here.
---------------------------------------------
Oxidation no. of Hydrogen = +1
Oxidation no. of Oxygen = -2
Now,
Since H2SO3 is charge less.
Therefore,
H2 SO3 = 0
1(2) + S(1) + -2(3) = 0
2 +S - 6 = 0
S - 4 = 0
S = +4
Thus oxidation no. of Sulphur in H2SO3 is +4.
-------------------------------------------------------------------
Hope it helps....
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