Question

oxidation no of S in H2S2O8? explain solution properly

Answer 1

OXIDATION NUMBER OF S ( SULPHUR)

Let oxidation no. Of S be x.

H2 's O. N. = +2

O' s O. N. = - 2( 8) = -16

SO, + 2 + 2 ( x ) + ( - 16 ) = 0 ( Becz overall charge is zero).

2x - 14 = 0

x = + 14/ 2

x = +7

OXIDATION NUMBER OF S is +7.
This is wrong analysis as Oxidation number of Sulphur cannot be +7 as it varies only from - 2 to +6.

So, due to Peroxide linkage, it's ON. becomes +6.

Answer 2

The oxidation no of S in H2S2O8 is +7.

• H2S2O8 is the oxo acid of sulphur.
• It is also called marshalls acid or peroxodesulphuric acid.
• Let the oxidation state of sulphur is X.
• Now, we know the oxidation state of oxygen is -2 while the oxidation state of hydrogen is 1.
• 1×2 +2x +(-2)8 = 0
• -16+2+2x = 0
• x = 14/2 = +7

#SPJ2