Question

oxidation no of sulphur in s2o82-ion​

Answer 1

Answer:

7

Explanation:

oxidation no. of o2 is -2

{C2o8}^-2

2x+8(-2)=-2

2x-16=-2

2x=14

x=7

Answer 2

Answer:

The answer is 7

Explanation:

As the ionic value is -2

2(s)+8(o)=-2

2s+8(-2)=-2

2s+(-16)=-2

2s-16=-2

2s=-2+16

2s=14

S=7