Chemistry, asked by chandan502, 1 year ago

oxidation no of underline element Na H2 _p_O4 and K2 _Mn_O4.


chandan502: 1st me underline element P hai and second me Mn

Answers

Answered by BigSmoke
1
In NaH2PO4, the oxidation no. of P is +5
1+2+X-8=0
X= +5

In K2Mn04, the oxidation no. of Mn is +6
2+X-8=0
X= +6

Hope you get your answer.
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