oxidation no of underline element Na H2 _p_O4 and K2 _Mn_O4.
chandan502:
1st me underline element P hai and second me Mn
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In NaH2PO4, the oxidation no. of P is +5
1+2+X-8=0
X= +5
In K2Mn04, the oxidation no. of Mn is +6
2+X-8=0
X= +6
Hope you get your answer.
1+2+X-8=0
X= +5
In K2Mn04, the oxidation no. of Mn is +6
2+X-8=0
X= +6
Hope you get your answer.
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