Question

oxidation no. of underline part a) NaH2 PO4​

Answer 1

Answer:

Explanation:

Let the oxidation number(O.N.) of P be ‘x’

We know that,

O.N. of Na = + 1

O.N. of H = + 1

O.N. of O = -2

Therefore, we have,

1(+ 1) + 2(+1)1(x) + 4(2) = 0

1 + 2 + x-8 = 0

X = + 5

The O.N. of P is + 5.

Answer 2

Answer:

oxidation no. of Na=+1

oxidation no. of H=+1

oxidation no. of p=+5

oxidation no. of O=-2

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