oxidation number and valency of oxygen in OF2 are
Answers
Explanation:
What is the oxidation number and the valency of oxygen in OF2?
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To answer this question you have to recall the assigning the oxidation state rules.
1. OXIDATION STATES RULES:
a. Oxidation state for all atoms, in a pure element in its natural state, is zero.
b. The sum of the oxidation states of all of the atoms must be equal to zero on the molecule, or the net charge on the ion.
c. Oxidation state of ions of alkali metals (group 1) is always +1.
d. Oxidation state of ions of alkaline earth metals (group 2) is always +2.
e. Fluorine is always −1.
f. Hydrogen is ALMOST always +1.
g. Oxygen is ALMOST always −2.
h. Sulphide ion is −2, halides (anions of halogens) are always −1.
i. Polyatomic ions have the assigned charge.
j. If two rules are in conflict, the earlier rule is followed. (This rule is the last one).
Therefore, combining e, g and j the oxidation state of O in OF2 is 2+.
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Answer:
oxidation number is 2
Explanation:
valency of oxygen is 2