Question

Oxidation number of An in HAuCl4

Answer 1

H=+1
Cl=-1, Cl4=-4

+1+Au-4=0
Au=+3


Oxidation Number of Au is 3

Answer 2

Oxidation number of An in $HAuCl_4$ is 3.

Explanation:

• The compound given is $HAuCl_4$  and we know the charge on hydrogen is +1 and the charge on chloride ion is -1.
• There are a total of 4 chlorine ions so, the charge on chlorine ion will be -4.
• As we know the compounds are neutral which means the total charge is 0.
• So, Charge on $H^+$ Charge on $Au^+$ Charge on chlorine ion is equal to 0.

          1 + Au + (-4) = 0

         -3 + Au = 0

         Au = 3

Hence, the oxidation number of Au is 3.

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