oxidation number of Boron in H3 BO3
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The oxidation state of B will be +3 bcz Hydrogen has oxidation state +1 and oxygen has oxidation state -2 .By putting u will get B-3,take the three to the other side and u will find ur answer
+1×3+B+3×-2
B+3–6=0
B-3=0
B=+3
Hope will be helpful ☺️
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