Oxidation number of C in C6H14?
Answers
Answered by
1
Answer:
x = -7/3
Explanation:
Using rules of oxidation number:
H : +1 in case on pairing with non metals (C)
It is a neutral compound, so sum of all oxidation number(s) is 0
Let oxidation number of C be x:
(x × 6) + (1 × 14) = 0
6x + 14 = 0
6x = -14
x = -14/6
x = -7/3
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Answered by
3
Answer:
C = 6
Explanation:
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