Question

Oxidation
number of CH in cuso4 is​

Answer 1

Answer:

We could substitute in the oxidation numbers of the sulphur and oxygen atoms, and apply the rule that in a compound the sum of all the oxidation numbers must come to zero. In this case, the oxygen atoms have -2 oxidation number, and sulphur +6, so (4 x -2) + 6 = -2 so the copper must be +2.

Answer 2

Answer:

Oxidation number of Cu is +2.

Explanation:

It seems you are asking for the oxidation number of Cu instead of CH.

Here are two ways of approaching this problem: Recognize CuSO 4 as an ionic compound containing a copper ion and a sulfate ion, SO42-. To form an electrically neutral compound, the copper must be present as a Cu2+ ion. The oxidation state is therefore +2.