Oxidation number of CH2F2 step by step
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suppose I have to find oxidation number for corbon then suppose the oxidation number of corbon is x
then 2(o.n. of H)+ x +2(o.n. of F)=0
2(1)+x+2(1)=0
x+4=0
X=-4
so the o.n. of corbon is -4
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