Oxidation number of Cl in CaOCI, (bleaching powder) is
(a) zero, since it contains Cl,
(b) -1, since it contains CH
(c) +1, since it contains CIO-
(d) +1 and -1, since it contains ClO and CH
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I think C
As it contains ClO- = -1
x+(-2)=-1
x-2=-1
x=-1+2
x=+1 is the oxidation state of Cl in CaOCl
As it contains ClO- = -1
x+(-2)=-1
x-2=-1
x=-1+2
x=+1 is the oxidation state of Cl in CaOCl
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