oxidation number of cr in Cr2O^2-
Answers
Answered by
2
Answer:
I think answer is +12.............
Answered by
3
Answer:
6
Explanation:
The oxidation number of chromium in dichromate is(Cr2O7^2-)
2x+7×(-2)=-2 (Oxidation number of Oxygen is -2)
2x=-2+14
2x=12
x=12÷2
x=6
Please mark it as the brainliest
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