Question

Oxidation number of cr in H2CrO8

Answer 1

Let Oxidation Number of Cr be x

2*1 + x + (-2)*8=0

because it is a molecule

2+x-16=0

-14+x=0

x=14

But maximum Oxidation number of Cr is 6

Hence Oxidation Number of Cr is 6

There is the presence of peroxide linkage