oxidation number of Cr in K3CrO8 is
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K (potassium) is an alkali metal so it has +1 oxidation number in pretty much all its compounds. O (oxygen) typically has -2 oxidation number (but see below). The overall compound is neutral. Therefore we have 3 * (+1) + x + 8 * (-2) = 0, and some algebra gives us x = oxidation number of Cr = +13.
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↪️ Oxidation State↩️
Potassium is alkali metal so mostly it has oxidation state of +1.
Here oxigen has oxidation state of -2.
And overall charge on compound is 0 (neutral).
Now , let oxidation number of Cr be X.
so ,
=> 3 × 1 + X + 8 × -3 = 0
X = +13
Hence , Oxidation number of Cr in compound K3CrO8 is +13.
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