Question

oxidation number of each atom of H3BO3​

Answer 1

The oxidation number of each atom of $H_{3}$\times\B$O_{3}$ are" + 1(H), + 3(B) and - 2(O)".

Explanation:

Oxidation number for hydrogen(H),

We know that,

B  = + 3 and O = - 2

∴ 3H + (+ 3) + 3( - 2) = 0

⇒ 3H + 3 - 6 = 0

⇒ 3H = 3

∴ H = + 1

Oxidation number for Boron(B),

We know that,

H  = + 1 and O = - 2

∴ 3( + 1) + B + 3( - 2) = 0

⇒ 3 + B - 6 = 0

⇒ B = + 3

∴ B = + 3

Oxidation number for Oxygen(B),

We know that,

H  = + 1 and B = + 3

∴ 3( + 1) + (+ 3) + 3( O) = 0

⇒ 6  +  3(O)= 0

⇒ 3(O) = - 6

∴ O = - 2

Hence, oxidation number of each atom of $H_{3}$B$O_{3}$ are" + 1(H), + 3(B) and - 2(O)".

Answer 2

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Oxidation number of each atom of H_{3}} BO_{3} are

+ 1(H) , + 3(B) and - 2(O)