Question

Oxidation number of each oxygen in sulphur dioxide is
-1(divided by)2
. Its example is

a) SO2

b) CHO

c) KO2

d) COOH

Answer 1

ANSWER

KO2

EXPLANATION

oxidation number in ko2 is -1/2

and in other compounds it is different

question say anything but at last it asked that

example of compound that have oxidation number -1/2

HOPE IT HELPS

BYE

Answer 2

Answer:

c) KO2

Explanation:

Oxidation number of each oxygen in sulphur dioxide is

-1(divided by)2

. Its example is KO2