Oxidation number of element S in SO4
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Answer:
the correct answer is +6
Explanation:
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Answered by
0
Answer:
hi
Explanation:
SO2−4 has a total charge of −2 , and oxygen is more electronegative than sulfur. So, oxygen polarizes the electron density towards itself more, and thus has the more negative oxidation state here. ⇒ x gives the oxidation state of sulfur, which is +6 . But keep in mind that this is unrealistic..
+6
The sum of the oxidation numbers in a polyatomic ion is equal to the charge on the ion. The oxidation number of the sulfur atom in the SO42- ion must be +6, for example, because the sum of the oxidation numbers of the atoms in this ion must equal -2.
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