Oxidation number of Fe4[Fe(CN)6]
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The formula is Fe4[Fe(CN)6]3
then the oxidation state of outer fe is +3 and oxidation number of fe in complex is +2.
based on criss cross method
from formula we can write
Fe+3&[Fe(CN)6]4-
by solving the complex
fe+6(-1)=-4. [oxidation state of CN is-1]
fe=-4+6=+2.
hope u understood.
roopiniP:
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