Question

oxidation number of H2S2O7

please solve this answer ​

Answer 1

Answer:

6

Explanation:

2 (oxidation number of hydrogen) + 2 (oxidation number of sulphur) + 7 (oxidation number of oxygen) = 0

Thus, by putting the oxidation number of respective elements,

 2(+1)+2(x)+7(−2)=02(+1)+2(x)+7(−2)=0

Therefore, 2+2x−14=02+2x−14=0

Therefore, 2x=122x=12

Therefore, x=6

Answer 2

Answer:

oxidation no of H2S2O7 is 6

Explanation:

as H= +1

S=?? let x

0= -2

then for above

by putting values we get

(1×2)+2x +(7×(-2)) =0

so x = +6