oxidation number of H4PO2
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Answer:
+1
Explanation:
Let the oxidation number of P in H4PO2 be x. The oxidation states of H and O are +1 and −2 respectively. Since the atom as whole is single negatively charged, following equation holds true:
2×(+1)+1×(x)+2×(−2)=−1
⟹2+x−4=−1
⟹x=4−2−1
⟹x=4−3
⟹x=+1
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