Oxidation number of Iodine in H4IO6-
Answers
Answered by
2
Answer:
H = 4
I = 1
O = 6
hope it helps...
Answered by
10
Explanation:
Oxidation number of H4IO6-
is +7
We calculate it by formula
H=+1
O=-2
I=x(let)
(+1×4)+x+(-2*6)=-1
x=+7
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