Oxidation number of nitrogen in ammonium sulphate
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Answer:
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Answer:
To easily determine the oxidation number on an individual atom in an ion it is necessary to write an equation.
First determine what the oxidation number of your known atoms are.
In this case, we know the oxidation number for H is +1.
Then set this value equal to the overall net charge of the ion.
In this case, it is +1.
Our equation now looks like this: 1(4) = 1, You use the multiplier of 4 to indicate that the ammonium ion has 4 hydrogen.
Next substitute a variable in the equation for the missing oxidation number:
+1(4) + N = +1
+1(4) + N = +1
Solve for N.
+1(4) + N = +1
Solve for N.
+1(4) + N = +1
+1(4) + N = +1
Solve for N.
+1(4) + N = +1N + 4 = +1
+1(4) + N = +1Solve for N.+1(4) + N = +1N + 4 = +1N = +1 - 4
+1(4) + N = +1Solve for N.+1(4) + N = +1N + 4 = +1
N = +1 - 4
N = -3
Thus, the oxidation number for Nitrogen is -3.
Explanation:
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