Question

Oxidation number of number of sulphur in Na2S2O8

Answer 1

Answer:

+6

Explanation:

S2O8 will have -2 charge according to Na, because the equation needs to be equal to zero.

Now, in S2O8 there are 2 peroxides, so they will take -1 charge. This leaves us with S2O6, where oxygen takes -2 charge.

Thus making the total charge of Oxygen -14. [ 2*(-1) + 6*(-2) ]

Sulfur's charge has to be a number that will be multiplied with 2, in order to give a -2 charge of the compound (S2O8):

2*(x) + (-14) = -2, so

2x = 12

x = +6 (charge of Sulfur)

Answer 2

Answer:

The Oxidation number will be +6 for each Sulphur.

Explanation:

According to Na, S2O8 will have a -2 charge because the equation must equal zero. Because there are two peroxides in S2O8, they will take a -1 charge. As a result, we have S2O6, in which oxygen has a -2 charge.

As a result, Oxygen has a total charge of -14 [2 × (-1) + 6 × (-2)]

The charge of Sulphur must be a quantity that can be multiplied by 2 to give the compound a -2 charge (S2O8).

Final calculation:

2 × (x) + (-14) = -2

2x = 12

x = +6

Thus, the oxidation number is the total number of electrons that an atom acquires or sheds in order to form a chemical bond with some other atom.