Question

oxidation number of oxygen is + 2 in which of the following compound
a. H2O
b. H2O2
c. OF2
d. O2F2​

Answer 1

Answer:

Ans is C

Explanation:

Now ..it is easy to find the OS in compounds ..let me show you how

First let the OS of the atom to be founded be X .

Now check the sign on the compound given...

Here all neutral compound are given hence net charge /sign =0

Frame a eq. Using the charges like here in C

Charge on each F = -1

There are 2F there fore the charge is -2

Hence the eq. Will be

X -2= 0

X=2

Note : always take the no. Of atoms in the counting

For example in D

It will be 2X ( as two O atoms are there)

2X -2 =0

X=1 (wrong ans. )

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Answer 2

Answer:

C

Explanation:

Flourine is the most electronegative compound hence its oxidation no always remains -1 so for the compound to remain electrically neutral oxidation state of oxygen has to be +2