Question

oxidation number of P in H4P2O3​

Answer 1

Answer:

+3

Explanation:

olecular formula =KH  

2

​  

PO  

3

​  

 

Overall charge on compound =0

Oxidation no. of oxygen in compound =−2

Oxidation no. of hydrogen in compound =+1

Oxidation no. of potassium in compound =+1

Let the oxidation no. of phosphorous be x.

Sum of oxidation no. of atoms = overall charge on atom

⇒1×(+1)+2×(+1)+1×x+3×(−2)=0

⇒1+2+x−6=0

⇒x−3=0

⇒x=+3