Chemistry, asked by beherarajib2020, 28 days ago

Oxidation number of'pt'in [pt(NH3)(H2O)Cl2] is​

Answers

Answered by Athul4152
2

 \huge\sf\underline{\underline{GIVEN :-}}

 \sf{ [pt (NH_{3})(H_{2}O)Cl_{2}]}

 \huge\sf\underline{\underline{To \: Find :-}}

Oxidation number of 'pt '

 \huge\sf\underline{\underline{Solution :-}}

 \sf{ pt (NH_{3})(H_{2}O)Cl_{2}} = 0

 \sf{x + 0 + 0 +( 2×-1) = 0 } \: \: \: [ Cl = -1 ]

 \sf {x - 2 = 0}

 x = +2

 \rule{10cm}{0.035cm}

oxidation number of pt = +2

Answered by ajr111
1

Answer:

+2

Explanation:

Here, there is no charge on the complex

That means the complex is a neutral complex

Oxidation number of the complex is '0'

Now,

Seeing the complex numbers of ligands in the complex

NH₃ = 0

H₂O = 0

Cl = -1

Now equating the oxidation numbers,

Before that, let us assume Oxidation number of 'Pt' be x

x + 0 + 0 + 2(-1) = 0

x - 2 = 0

x = +2

That means oxidation number of Pt is +2

Hope it helps

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